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In other words, when the compiler starts building your code, no #define statements or anything like that is left In my project, the program can do one thing of two, but never both, so i decided that the best i can do for one class is to define it depending of a #define preprocessor variable A good way to understand what the preprocessor does to your code is to get hold of the preprocessed output and look at it.
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As far as i know, what you're trying to do (use if statement and then return a value from a macro) isn't possible in iso c.but it is somewhat possible with statement expressions (gnu extension) Still, it is something to keep in. I've found that this works on gcc and clang by default:
What is the point of #define in c++
I've only seen examples where it's used in place of a magic number but i don't see the point in just giving that value to a variable instead. The #define directive is a preprocessor directive The preprocessor replaces those macros by their body before the compiler even sees it Think of it as an automatic search and replace of your source code
A const variable declaration declares an actual variable in the language, which you can use.well, like a real variable Take its address, pass it around, use it, cast/convert it, etc How can i use #if inside #define in the c preprocessor Asked 15 years, 6 months ago modified 7 months ago viewed 51k times
So i read the interesting answers about what are the differences between constexpr and const but i was curious about are the differences between #define and constexpr
I feel like constexpr is jus. How do i define a function with optional arguments Asked 13 years, 8 months ago modified 1 year, 4 months ago viewed 1.2m times #define _add_penguin(a) penguin ## a #define add_penguin(a) _add_penguin(a) #define width (100) #define height 200 add_penguin(height) // expands to penguin200 add_penguin(width) // error, cannot concatenate penguin and (100) same for stringization (#)
Clearly this is a corner case and probably doesn't matter considering how width will presumably be used
