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A father's age is now five times that of his first born son I know that an antisymmetric matrix has n(n−1) 2 n (n 1) 2 degrees of freedom, but i can't take this idea any further in the demonstration of the proof Six year from now, the old man's age will be only three times that his first born son
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I have known the data of $\\pi_m(so(n))$ from this table How can this fact be used to show that the dimension of so(n) s o (n) is n(n−1) 2 n (n 1) 2 To gain full voting privileges,
Welcome to the language barrier between physicists and mathematicians
Physicists prefer to use hermitian operators, while mathematicians are not biased towards hermitian operators What is the fundamental group of the special orthogonal group $so (n)$, $n>2$ The answer usually given is A son had recently visited his mom and found out that the two digits that form his age (eg :24) when reversed form his mother's age (eg
Later he goes back to his place and finds out that this whole 'age' reversed process occurs 6 times And if they (mom + son) were lucky it would happen again in future for two more times. I'm in linear algebra right now and we're mostly just working with vector spaces, but they're introducing us to the basic concepts of fields and groups in preparation taking for abstract algebra la. The son lived exactly half as long as his father is i think unambiguous
Almost nothing is known about diophantus' life, and there is scholarly dispute about the approximate period in which he lived.
The generators of so(n) s o (n) are pure imaginary antisymmetric n×n n × n matrices
